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3 years ago

How do you find the perimeter again? Worth 40 points!

Mathematics

1 answer:

zysi [14]3 years ago

8 0

Answer:

↓↓↓↓↓

Step-by-step explanation:

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle. The area is measurement of the surface of a shape.

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1) Solve for x. x+23=−22 2) Solve for a. a+(−1.3)=−4.5

8090 [49]

X+23=-22
-23 -23

x=-45

a+(-1.3)=-4.5

or

a-1.3+-4.5
+1.3 +1.3

a=3.2

6 0

3 years ago

Read 2 more answers

PLZ HELP!!!!!! (WILL GIVE BRAINLIEST!!!!) Number 4 only

Elan Coil [88]

Figure B, it's volume is 48 while figure A is 36

4 0

3 years ago

Please help me with this

xenn [34]

Step-by-step explanation:

based on my understanding of the dreidel, this is a regular spinner with 4 equal sides (but different symbols on them, so, we can clearly distinguish between the possible 4 different outcomes).

in other words, this resembles a die with only 4 sides and therefore only 4 equally probable outcomes.

and therefore, the probability to get the specified symbol in 1 attempt is indeed 1/4.

remember, a probability is always desired cases over totally possible cases.

and here, we have one desired outcome out of 4 possible outcomes. hence the probability of 1/4.

now, we are spinning the dreidel twice.

that means we have now 4×4 = 16 possible outcomes.

but we only want the outcomes, where the specified symbol is showing exactly once - either after the first spin or after the second spin.

so, out of the 16 possible combinations, we want only the ones, where the first spin delivered that result :

1 option on the first spin and 3 options (4 minus the already delivered result) on the second spin : 1×3 = 3.

and the ones, where the second spin delivered the result (but not the first). so, we have 3×1 = 3 options there.

that means we have 6 desired cases out of total 16 possible outcomes, and the probability is

6/16 = 3/8

mathematically we would simply say that the probability is the sum of

the probability of spinning it first combined with the probability of not spinning it second.

the probability of not spinning it first combined with the probability to spin it second.

that is

1/4 × 3/4 = 3/16

3/4 × 1/4 = 3/16

-----------------------

6/16 = 3/8

I don't know the options you can select, but I hope you understand the principles I explained. and I gave you the result and the way to calculate it.

so, hopefully you find the fitting options.

8 0

2 years ago

Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2

kifflom [539]

Answer:

The solution of the differential equation is $y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

i) Using characteristic equation:

The characteristic equation method assumes that y(t)= $e^{rt}$ , where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

$y'=re^{rt}$

$y"=r^{2}e^{rt}$

$r^{2}e^{rt}+e^{rt}=0$

$(r^{2}+1)e^{rt}=0$

As $e^{rt}$ could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

$y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}$

Using Euler's formula:

$y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]$

$y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)$

$y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)$

The particular solution of the differential equation is given by:

$y(t)_{p}=ASin(2t)+BCos(2t)$

$y'(t)_{p}=2ACos(2t)-2BSin(2t)$

$y''(t)_{p}=-4ASin(2t)-4BCos(2t)$

So we use these derivatives in the differential equation:

$-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)$

$-3ASin(2t)-3BCos(2t)=Sin(2t)$

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

$y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)$

Using the initial conditions we can check that C1=5/3 and C2=2

ii) Using Laplace Transform:

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]= $\frac{2}{(s^{2}+4)}$

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) = $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)-2s-1= $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)= $\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}$

Y(s)= $\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}$

Y(s)= $\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}$

Using partial franction method:

$\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}$

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)= $\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}$

Y(s)= $-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}$

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[ $-\frac{1}{3} \frac{2}{s^{2}+4}$ ]-ℒ⁻¹[ $2\frac{s }{s^{2}+1}$ ]+ℒ⁻¹[ $\frac{5}{3}\frac{1}{s^{2}+1}$ ]

$y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

3 0

3 years ago

Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?

grandymaker [24]

-2m - 5m = -7m
-7m - 8 = 3 -7 + m
3 - 7 = -4
-7m - 8 = m - 4
-7m - 8 + 8 = m - 4 + 8
-7m = m + 4
-7m - m = m + 4 - m
-8m = 4
-8m/-8 = 4/ -8
FINAL = m= -1/2 = -0.5

4 0

3 years ago