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Anni [7]
3 years ago
10

You buy painting supplies for $12, and you charge $3 per person to paint faces. how many faces will you need to paint to earn $1

5 in profit?
Mathematics
2 answers:
NikAS [45]3 years ago
6 0

Investment = $12

For $15 profit, I have to earn, 12+15 = $27

Charge for 1 person(for paint faces) = 3

multiply by 9,

9 persons= $27

So, 9 person is the answer.

Scorpion4ik [409]3 years ago
3 0

Answer:

You need to paint 9 faces to earn $15 in profit.

Step-by-step explanation:

Given : You buy painting supplies for $12, and you charge $3 per person to paint faces.

To find : How many faces will you need to paint to earn $15 in profit?

Solution :

Let x represent the number of faces painted.

According to question,

3x - 12 = 15

Solving equation,

3x= 15+12

3x=27

x=\frac{27}{3}

x=9

Therefore, You need to paint 9 faces to earn $15 in profit.

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
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<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
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  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

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Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

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