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Rina8888 [55]
3 years ago
12

Consider the equation below.

Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

The equation has no solutions .

Step-by-step explanation:

Given as :

<u>The linear equation is </u>

\dfrac{3}{4}(24 -16 x) = \dfrac{-2}{3}(18 x -27)

Or, \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x -  \dfrac{-2}{3} × 27

Or,  \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x + \dfrac{2}{3} × 27

Or, \frac{3\times 24}{4} -  \frac{3\times 16 x}{4} =  \frac{-2\times 18 x}{3} + \frac{2\times 27 x}{3}

Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9

Or, 18 - 12 x = - 12 x + 18

Or, 18 - 18 = - 12 x + 12 x

or, 0 = 0

∵ The linear equation has no variables , so the equation has no solution

Hence,The equation has no solutions . Answer

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What is the solution to the following equation?<br> 17 n -23n + 11.5n = 44
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Isolate the variable by dividing each side by factors that don't contain the variable.

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Step-by-step explanation:

Have a nice day! I hope this helps!

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Find the distance between the lines<br> Y=3x+10<br> Y=3x-20<br> AND <br> Y=3/2x+3/2<br> Y=3/2x-5
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At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope 
If we have two parallel lines ⇒ y₁ = mx + c₁   and    y₂ = mx + c₂
So, the distance between y₁ and y₂ = d = \frac{|c_{1} - c_{2}|}{\sqrt{1 + m^{2}}}
========================================================

Part (1):
=======

<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10    and       Y₂ = 3x - 20</span>
∴ m = 3  , c₁ = 10  and  c₂ = -20
∴ d = \frac{| 10 - (-20)|}{\sqrt{1 + 3^{2}}}= \framebox{9.5}

========================================================

Part (2):
=======

<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span>    and       Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5  , c₁ = 3/2 = 1.5   and  c₂ = -5
∴ d = \frac{| 1.5- (-5)|}{\sqrt{1 + 1.5^{2}}}= \framebox{3.6}

6 0
3 years ago
Which expression is equivalent to sqrt128x^5y^6/2x^7y^5 ? Assume x 0 and y &gt; 0.
kolbaska11 [484]

<u>Answer:</u>

\frac{8\sqrt{y} }{x}

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it:

\sqrt {\frac {128x^5y^6} {2x^7y^5} }

To make it easier to solve, we can also write this expression as:

\sqrt {\frac{128}{2} * \frac {x^5} {x^7} * \frac {y^6} {y^5}}

Now we will cancel out the like terms to get:

\sqrt {64*\frac{1} {x^2}*y }

Taking the square root of the terms to get:

8*\frac {1}{x} .\sqrt{y}

\frac{8\sqrt{y} }{x}

4 0
3 years ago
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