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Rina8888 [55]
2 years ago
12

Consider the equation below.

Mathematics
1 answer:
Eduardwww [97]2 years ago
8 0

Answer:

The equation has no solutions .

Step-by-step explanation:

Given as :

<u>The linear equation is </u>

\dfrac{3}{4}(24 -16 x) = \dfrac{-2}{3}(18 x -27)

Or, \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x -  \dfrac{-2}{3} × 27

Or,  \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x + \dfrac{2}{3} × 27

Or, \frac{3\times 24}{4} -  \frac{3\times 16 x}{4} =  \frac{-2\times 18 x}{3} + \frac{2\times 27 x}{3}

Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9

Or, 18 - 12 x = - 12 x + 18

Or, 18 - 18 = - 12 x + 12 x

or, 0 = 0

∵ The linear equation has no variables , so the equation has no solution

Hence,The equation has no solutions . Answer

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Step-by-step explanation:

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3 years ago
Find the average rate of change for the given function from x = −1 to x = 2.
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Well, if you look at the graph, when x = -1, y or f(x) = 4.

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8 0
3 years ago
The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

4 0
2 years ago
Read 2 more answers
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