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Rina8888 [55]
2 years ago
12

Consider the equation below.

Mathematics
1 answer:
Eduardwww [97]2 years ago
8 0

Answer:

The equation has no solutions .

Step-by-step explanation:

Given as :

<u>The linear equation is </u>

\dfrac{3}{4}(24 -16 x) = \dfrac{-2}{3}(18 x -27)

Or, \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x -  \dfrac{-2}{3} × 27

Or,  \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x + \dfrac{2}{3} × 27

Or, \frac{3\times 24}{4} -  \frac{3\times 16 x}{4} =  \frac{-2\times 18 x}{3} + \frac{2\times 27 x}{3}

Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9

Or, 18 - 12 x = - 12 x + 18

Or, 18 - 18 = - 12 x + 12 x

or, 0 = 0

∵ The linear equation has no variables , so the equation has no solution

Hence,The equation has no solutions . Answer

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PLS show the work and help me PLS :(
emmasim [6.3K]
All of the steps are good up until the 25-0, instead a 0 should have put into the top and the 1 brought down so that it was 251-248 which gets you 3 as a remainder so the answer is 804 R3
3 0
3 years ago
A diver dives from a 10m springboard. the equation f(t) = -4.9t² + 4t + 10 models her height above the pool at time t. When will
Gennadij [26K]

Answer:

At time t = 0.408 sec diver will be at maximum height

Step-by-step explanation:

We have given equation of the height f(t)=-4.9t^2+4t+9

We know that velocity is the rate of change of distance with respect to time

So v=\frac{df(t)}{dt}=\frac{df(-4.9t^2+4t+10)}{dt}=-9.8t+4+0=-9.8t+4

At maximum height velocity will be zero

So -9.8t+4=0

t = 0.408 sec

So at time t = 0.408 sec diver will be at maximum height

5 0
2 years ago
What is the value of this expression 1/3-5
gregori [183]
The answer is 243 for the question above
5 0
3 years ago
Read 2 more answers
1+sec^2xsin^2x=sec^2x
Sholpan [36]
1 + sec^2(x)sin^2(x) = sec^2(x)
This becomes
1+tan^2(x) = sec^2(x) which is an identity
You could
1 + sin^2(x)/cos^2(x) = sec^2(x)
then
cos^2(x) + sin^2(x) = cos^2(x)sec^2(x)
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4 0
3 years ago
Read 2 more answers
Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.
Galina-37 [17]

Answer:

AD \parallel BC

AB \parallel CD

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0

The slope of side BC is

M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1

The slope of side CD is

M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0

The slope of AD is

M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1

AD \parallel BC

AB \parallel CD

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

4 0
3 years ago
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