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AlladinOne [14]
3 years ago
12

How to write 800+10+4 in standard form

Mathematics
2 answers:
Dominik [7]3 years ago
8 0
Their are 3 ways. 1. Eight hundred and fourteen 2. 814 3. 800 + 10 + 4
sertanlavr [38]3 years ago
3 0
814
800+10+4
Eight Hundred and FourTeen
(3 ways)
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Which term describes 2x + 5 = 17?
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Answer:

Expression

Step-by-step explanation:

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What is the value of k in the product of powers below?<br> 1<br> 0<br> -1<br> -3
Marysya12 [62]
It looks like the pattern reversed after 0. So you would subtract 1 then 2 and then 3.
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The sum of the speeds of two trains is 724.3 miles per hour. If the speed of the first train is 11.7 mph faster than that of the
oee [108]

Answer:

A=368 miles

B= 356.3 miles

Step-by-step explanation:

Given data

Let the two trains be A and B

A+B=724.3----------1

A-B=11.7--------------2

From eqn 1

A= 724.3-B

put this in place of A in eqn 2

724.3-B-B= 11.7

724.3-2B= 11.7

724.3-11.7= 2B

712.6=2B

B= 712.6/2

B= 356.3 miles

Put B=356.3 in eqn 1

A+356.3=724.3----------1

A= 724.3-356.3

A=368 miles

8 0
3 years ago
1) y=mx+b (solve for b)<br>2) t=an+b (solve for n)
astra-53 [7]
The equation is already solved for the variable t To solve for any other variable simply rearrange theequation to have the indicated variable on one sideof the equals sign and everything else on the other. For example, to solve for a: t=an+b       subtract b from both sidest-b = an      divide both sides by n(t-b)/n = a Or:  a = (t-b)/n Work in the same manner to solve for either b or n: b = t-an n = (t-b)/a
7 0
3 years ago
6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0
2 years ago
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