Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>142</u></em><em><u>°</u></em></h2>
Step-by-step explanation:
This is because,
They are <em><u>Vertically</u></em><em><u> </u></em><em><u>Opposite</u></em><em><u> </u></em><em><u>Angles</u></em><em><u>. </u></em>
Hello damerahli!
Find the landmark.
Let's take a look at the graph. The coordinates given are (2, ¼).
This means that...
- Coordinate at abscissa = 2
- Coordinate at ordinate = ¼
In the graph given, each square = ¼ units. That means the 1st box above the origin in the ordinate is (0, ¼). Let's mark this as our coordinate of y-axis. Then let's take 2 in the abscissa (2, 0) as the other coordinate. So, by connecting the 2 points (since both the coordinates are positive they'll lie in the 1st quadrant) we can see that the landmark is the 
. (Marked as a yellow dot in the attached figure).
<em>Please </em><em>refer </em><em>to </em><em>the attached</em><em> picture</em><em> for</em><em> better</em><em> understanding</em><em>.</em>
__________________
Hope it'll help you!
ℓu¢αzz ッ
Answer:
195 inches³
Step-by-step explanation:
Volume = Length * Width * Height
Write as a decimal
2 1/2 = 2.5
Volume = 13 * 6 * 2.5
Volume = 195 inches³
Hope this helps :)
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
