The vertex angle bisector divides the triangle into two congruent right triangles. The sine of half of the vertex angle will be half of the base divided by the side (from the definition of the sine of an angle). Then the total vertex angle is ...
α = 2×arcsin(3.5/5) ≈ 88.9°
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Using the Law of Cosines, the vertex angle can be found as
arccos((7^2 -5^2 -5^2)/(-2*5*5)) = arccos(1/50) ≈ 88.9°
8.625 is the correct answer.
Answer:
oh so for one get them to look alike.. sooo keep 5/16 and change 1 7/8 to
1 14/16 and then change it to 30/16 then simply compare 5 can go into 30 6 times soooooo it can go into 1 & 7/8 6 times
Step-by-step explanation:
Answer:
C i think but im not 100% sure
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