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SSSSS [86.1K]
3 years ago
7

Can someone help me with these 2 answersss

Mathematics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

1. -12

2. 8

Step-by-step explanation:

We are given two equations, both with meanings of variables, making my job a little bit easier wink wink.

Let's start with 5x + 3 when x = -3

Substitute :

5(-3) + 3

-15 + 3

-12

Onto the next :

2x - 4 if x = 6

2(6) - 4

12 - 4

8

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A (blank) in matter results in a change in its identity and properties. Which best completes the statement?
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Answer:

Hi there!

Your answer is:

A. Chemical change

Step-by-step explanation:

Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

6 0
3 years ago
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A graph shows the horizontal axis numbered 1 to 5 and the vertical axis numbered 1 to 5. points and a line show a downward trend
andrezito [222]

The  most likely correlation coefficient for the set of data shown is: -0.21.

<h3>Correlation coefficient</h3>

We would be using CORREL in excel to determine the correlation coefficient by inputting the set data below

X Y

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2 years ago
Find the perimeter of the figure if a = 1, b = 4, c = 6, d = 5. ​
anygoal [31]

Answer:

16

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5 0
3 years ago
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
AfilCa [17]
Given a solution y_1(x)=x^4, we can attempt to find another via reduction of order of the form y_2(x)=x^4v(x). This has derivatives

{y_2}'=4x^3v+x^4v'
{y_2}''=12x^2v+8x^3v'+x^4v''

Substituting into the ODE yields

x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0
x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0
x^6v''+x^5v'=0

Now letting u(x)=v'(x), so that u'(x)=v''(x), you end up with the ODE linear in u

x^6u'+x^5u=0

Assuming x\neq0 (which is reasonable, since x=0 is a singular point), you can divide through by x^5 and end up with

xu'+u=(xu)'=0

and integrating both sides with respect to x gives

xu=C_1\implies u=\dfrac{C_1}x

Back-substitute to solve for v:

v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2

and again to solve for y:

y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2
\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), t=\ln x. You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.
6 0
4 years ago
LOOK AT PIC, ASAP, ROGHT ANSWER GETS BRAINLIEST !
k0ka [10]

Answer:

Step-by-step explanation:

The teacher has 7/8 pounds of clay given.

gives out 1/16 per station

7/8= 0.875 pound

7/8 / 1/16 pound= 14 maximum stations

14 stations divided by 2 classes = 7 in each room

5 0
3 years ago
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