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charle [14.2K]
3 years ago
10

What is the situation for these two equations ×=10+2 and 10x=2

Mathematics
1 answer:
Tom [10]3 years ago
5 0

Answer:

1 is x=12

2 is x= 1/5

Step-by-step explanation:

For equation number 1 you just add 10 and 2, which is 12.

For equation number 2 you divide 2 by 10 and simplify it to 1/5. So x = 1/5

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What’s one message you would tell your ex if you miss him/her a girl is heartbroken here get me in my feels XD
aalyn [17]

Answer:

Sadly all my exes were horrible and cheated on me however, I will tell you what I would say if I lost my current partner

Step-by-step explanation:

I regret not being there so much. I regret not loving you enough. I regret not holding you enough and not kissing you enough. I regret not spoiling you enough. I regret everything except loving you. I wish I could've given you the world like my promise and that was the biggest mistake yet.  

6 0
3 years ago
1. Is the relation a function and why or why not?<br> {(1, 2), (2, 3), (1, 6), (4,3)}
weqwewe [10]

Answer:

Its not a function, D

Step-by-step explanation:

its not a function because the x value, 1, repeats. input is x and output is y, so the input of 1 has more than one output.

7 0
3 years ago
Please answer quickly!
Damm [24]

Answer:

2.57 or 2.5703939893007399

Hope this helped have a good one! :)

6 0
3 years ago
The equation of a given circle in general form is x^2+y^2-8x+12y+27=0. Write the equation in standard form, (x-h)^2+(y-k)^2=r^2,
umka2103 [35]

Answer:

(x - 4)² + (y + 6)² = 5²

Step-by-step explanation:

rearrange the general equation as follows

collect the terms in x and y together and place the constant on the right side

x² - 8x + y² + 12y = - 27

add (half the coefficient of the x/y term)² to both sides

x² + 2(- 4)x + y² + 2(6)y = - 27

(x - 4)² + 16 + (y + 6)² + 36 = - 27 + 16 + 36

(x - 4)² + (y + 6)² = 25

(x - 4)² + (y + 6)² = 5² ← in standard form



7 0
3 years ago
How would i graph f(2x)=2x+3
SpyIntel [72]
See the attached, the line going vertically is at -0.7.

6 0
3 years ago
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