Hello,
The formula for finding the area of a circular region is:
then:
With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.
Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
Step-by-step explanation:
what is the question you are just showing us the lesson and modle
<h3>
Answer:</h3>
unshaded area = 25(4 -π) in^2 ≈ 21.46 in^2
<h3>
Step-by-step explanation:</h3>
Each of the shaded circles has a diameter of (20 in)/4 = 5 in, which also is the width of the enclosing rectangle. Then each circle has a radius of 2.5 in, and an area of ...
A = πr^2 = π(2.5 in)^2 = 6.25π in^2
The four circles together have an area of ...
4A = 4·(6.25π in^2) = 25π in^2
The area of the rectangle is the product of its length and width:
A = LW = (20 in)(5 in) = 100 in^2
Since the circles are shaded, the unshaded area is the difference between the rectangle area and the total area of the four circles:
unshaded area = (100 in^2) - (25π in^2) = 25(4 -π) in^2 ≈ 21.46 in^2
The angle sum of triangle is 180 degrees, so 180-125 = 55
Answer:
-6x^6 + 4x^4 - 3x^3 + 4x^2 + 12
Step-by-step explanation:
-6x^6 + 4x^4 - 5x^3 + 2x^3 + 4x^2 + 12
-6x^6 + 4x^4 - 3x^3 + 4x^2 + 12
