14 pigs are entered in the "best pig" competition at the county fair. The judges will award very special pigs with blue, red, an d white ribbons. In how many different ways can these ribbons be awarded to 3 of the 14 pigs. A. 2184 B. 364. C. 42. D. 2744
2 answers:
So the judges are going to pick 3 pigs from the 14 to give a ribbon. Since the ribbons are different, the order does matter. So this is a permutation. This can be set up like this:
Basically, this means we'll be multiplying 14*13*12, which is 2184. This makes A the correct answer :)
The answer is A You multiply 14*13*12 to get 2184
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Using the Distributive Property
The answer would be 3.
2 *4x = 8x and 2 * 3 = 6, to get 8x 6
Answer:
A. 56.54867 rounded to 56.56
Step-by-step explanation:
18/2=9
r=9
C=2πr=2·π·
C=2(3.14)(9)
9≈56.54867
The answer to this hard equation of Thai hard problem of this impossible thing the answer is 3
If you would like to write 7/8 as a decimal, you can do this using the following steps: 7/8 = (125*7)/1000 = 875/1000 = 0.875 = .875 The correct result would be b. .875.
Answer:
12(5y+4)
12(9y)
108y
hope it helps and I hope I did it right
Step-by-step explanation: