The only shape that has that much is a decagon 10 sides. t<span>he </span>sum<span> of the interior </span>angles of a Regular Decagon is 1440 degrees.
Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
10y + 29 ≤ -23
Step-by-step explanation:
subtract 29 from each side to get:
10y ≤ -52
y ≤ -5.2
Area of a square= l²
= 8×8 = 64 in²
Area of a circle= πr²
= π × 4²
= 50.3 in²
Difference = 64 - 50.3 = 13.7 in²
multiply 17 by 6%
17 * 0.06 = 1.02 increase
17 +1.02 = 18.02 new hourly wage