The discontinuous at the x-value for which the denominator was zero is removable, I hope this help
Answer:
m = 3
n = 14
p = 2
Step-by-step explanation:
7/x-3/2=(n-mx)/px
(7*2-3*x/2)/2x=(n-mx)/px
=>(14-3x)/2x = (n-mx)/px
now we will compare
LHS and RHS with terms containing X and terms not containing x
so
14 = n
-3x = -mx
m = 3
2x = px
p = 2
Thus,
values for m, n, and p
are 3,14 and 2 respectively.
Unfortunately, I do not go to Harvard Business School so I am unable to solve this complex equation.
