The velocity of the ship = 22 ∠157° = (22 cos 157°) i+ (22 sin 157°) j
The velocity of current = 5 ∠213° = (5 cos 213°) i+ (5 sin 213°) j
So, the resultant velocity = 22 ∠157° + 5 ∠213°
= (22 cos 157°) i+ (22 sin 157°) j + (5 cos 213°) i+ (5 sin 213°) j
= (22 cos 157° + 5 cos 213°) i + (22 sin 157° + 5 sin 213°) j
= -24.444 i + 5.873 j
= 25.14 ∠166.5°
The correct answer is option (1)
<span>1) 25 knots at 166.5 degree</span>
Answer:
32 students are in the class.
Step-by-step explanation:
8 * 4 = 32
<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!! :D</u></em>
<em><u>-XxDeathshotxX</u></em>
Answer:
Step-by-step explanation:
Shape Formula Sum Interior Angles
3 sided polygon (triangle) (3−2)⋅180 180∘
4 sided polygon (quadrilateral) (4−2)⋅180 360∘
6 sided polygon (hexagon) (6−2)⋅180 720∘
<u>Area of triangle = (1/2) × Base × Height</u>
Area of bigger triangle = (1/2) × 15 cm × 10 cm
Area of bigger triangle = (1/2) × 150 sq. cm
Area of bigger triangle = 75 sq. cm
Similarly,
Area of smaller triangle = (1/2) × 12 cm × 5 cm
Area of smaller triangle = (1/2) × 60 sq. cm
Area of smaller triangle = 30 sq. cm
Area of shaded region = Area of bigger triangle - Area of smaller triangle
Area of shaded region = 75 sq. cm - 30 sq. cm
Area of shaded region = 45 sq. cm
<u>Answer</u><u> </u><u>:</u>
Area of shaded region in sq. cm = 45
