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kow [346]
4 years ago
10

Can someone please help me :)

Mathematics
1 answer:
gavmur [86]4 years ago
7 0

Answer:

<em>90 degree</em>

Step-by-step explanation:

Three points A, B, and C are added and shown in attached picture.

As the property of inscribed angle in circle:

angle BAC = (1/2) x 88 = 44 deg

As the property of complement angle:

angle ABC = 180 - 89 = 91 deg

As the property of sum of three angles in a triangle:

angle ACB + angle ABC + angle BAC = 180 deg

=> angle ACB = 180 - angle ABC - angle BAC = 180 - 44 - 91 = 45 deg

One more time, we use the property of inscribed angle in circle:

x = 2 x angle ACB = 2 x 45 = 90 deg

Hope this helps!

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Heather is flying a kite at the park. The string makes an angle of 53° with the level ground. The kite is 28 meters above the gr
Snezhnost [94]

Answer:

35.06 meters

Step-by-step explanation:

This represents a right angled triangle.

The height of the kite above the ground represents the opposite side while the length of the string of the heather of the kite is the hypotenuse.

We need to find the hypotenuse, h.

We can use the sine part of the trigonometric function SOHCAHTOA:

sin(Ф) = opp / hyp

where opp is the side opposite the angle

hyp is the hypotenuse

=> sin(53) = 28 / h

h = 28 / sin(53)

h = 35.06 meters

The length of the string from the heather to the kite is 35.06 meters

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If you pick a card randomly from 52 cards, what is the probability that you get neither a red card nor a face card ?
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Are the segments through the origin and the points listed perpendicular? Explain.
Zinaida [17]

Answer:

a. Not perpendicular.

b. Perpendicular.

Step-by-step explanation:

We need to check whether the segments through the origin and the points listed perpendicular.

Product of slopes of two perpendicular lines is -1.

Slope=\dfrac{y_2-y_1}{x_2-x_1}

(a) The given points are (9,10) and (10,9).

Slope of line segment through (0,0) and (9,10) is

m_1=\dfrac{10-0}{9-0}=\dfrac{10}{9}

Slope of line segment through (0,0) and (10,9) is

m_2=\dfrac{9-0}{10-0}=\dfrac{9}{10}

Product of slopes is

m_1\cdot m_2=\dfrac{10}{9}\cdot \dfrac{9}{10}=1\neq -1

Therefore, the line segments through the origin and the points (9,10) and (10,9) are not perpendicular.

(b) The given points are (9,6) and (4,-6).

Slope of line segment through (0,0) and (9,6) is

m_1=\dfrac{6-0}{9-0}=\dfrac{6}{9}=\dfrac{2}{3}

Slope of line segment through (0,0) and (4,-6) is

m_2=\dfrac{-6-0}{4-0}=\dfrac{-6}{4}=-\dfrac{3}{2}

Product of slopes is

m_1\cdot m_2=\dfrac{2}{3}\cdot (-\dfrac{3}{2})=-1

Therefore, the line segments through the origin and the points  (9,6) and (4,-6) are perpendicular.

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