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Alinara [238K]
3 years ago
6

Aidan rollerblades 540 ft per min. at this rate how far in yards will he rollerblade in 5 min( 1 yd =3 ft)​

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

900 yards

Step-by-step explanation:

540/3=180

180x5=900

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Which of the following points lies on the line?
Bond [772]

Answer:

C. (3,-3)

Step-by-step explanation:

5x + 3y = 6

5(3) + 3(-3) = 6

15 + (-9) = 6

therefore point lies on the line

8 0
2 years ago
A town has a population of 2000 and grows at 4.5% every year. What will be the
goldfiish [28.3K]

Answer:

3544

Step-by-step explanation:

This is a problem of compound growth. The formula is

F=P(1+r)^t

Where F is the value in the future (in this case, the population after 13 years)

P is the intial amount (here, the initial population of 2000, so P = 2000)

r is the rate of growth (here, it is 4.5%, in decimal, 0.045)

t is the time frame (here, it is 13 years, so t = 13)

<em>we can plug the numbers into the formula and solve for F:</em>

<em>F=P(1+r)^t\\F=2000(1+0.045)^{13}\\F=2000(1.045)^{13}\\F=3544.4</em>

<em>rounded to the nearest whole number, the </em><em>population after 13 years would be 3544</em>

3 0
3 years ago
Read 2 more answers
Which shapes could this hexagon be decomposed into to find its area? Choose all that apply (3 points).
Scilla [17]
You can do:

-two trapezoids
-six triangles
-two parallelograms

You can't put it into one rectangle, that will definitely not work. 

As you can see from the attachment, triangles work, trapezoid as well, and two parallelograms. The one rectangle would not work.

I hope this helps!
~kaikers

 

3 0
3 years ago
3. Using techniques from Calculus, show directly that the maximum value of a 1-D Gaussian distribution occurs at the point x = μ
Vilka [71]

Answer:

For a scaler variable, the Gaussian distribution has a probability density function of

p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×e^{\frac{-(x-u)^{2}}{2s^{2} }  }

The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ

Step-by-step explanation:

Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion  

From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ

5 0
3 years ago
Find all numbers with the given absolute value<br> 1)12<br> 2)1.7<br> 3)3/5<br> 4)3 1/6<br> 5)0
telo118 [61]
It would be the negative form of those bumbers and the non-negative form of those numbers. The absolute value applies to negative numbers the same. For example absolute value of -3 is 3.
5 0
3 years ago
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