The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
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Answer:
Acute
Step-by-step explanation:
its Acute because acute angles are small like this one!
Answer:
Length = 8 m
Width = 30 m
Step-by-step explanation:
Let length = x.
Then width = 3(x + 2).
P = 2(L + W)
76 = 2[x + 3(x + 2)]
76 = 2[x + 3x + 6]
76 = 2[4x + 6]
8x + 12 = 76
8x = 64
x = 8
3(x + 2) = 3(10) = 30
Answer:
Length = 8 m
Width = 30 m
Answer:
3
Step-by-step explanation:
Answer:
£13750
Step-by-step explanation:
263750- 250000 = 13750
