Question

If dy/dx = x(y-1), find the equation of the tangent line at x=-2 with f(-2)=3

Answer 1

Answer:

The equation of the tangent line passing through the point (-2,3) is

 4 x + y +5 =0

Step-by-step explanation:

Step(i):-

Given that the slope of the tangent

             $m = \frac{dy}{dx} = x(y-1)$

             m = -2( 3-1) = -4

Given point x = -2

         y = f(-2) =3

∴The given point ( x₁ , y₁) = ( -2 ,3)

Step(ii):-

The equation of the tangent line passing through the point (-2,3)

$y - y_{1} = m(x-x_{1} )$

$y -3 = -4(x-(-2))$

y -3 = -4( x+2)

y-3 = -4x -8

4x + y -3+8=0

4x +y +5=0

Step(iii):-

The equation of the tangent line passing through the point (-2,3) is

  4 x + y +5 =0