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3 years ago

Which of the properties are correct about slope

Mathematics

1 answer:

pantera1 [17]3 years ago

6 0

A and e is your answer

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kent can paint a certain room in 6 hours, but Kendra needs 4 hours to paint the same room. How long does it take them to paint t

Ulleksa [173]

About 2 and a half hours

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3 years ago

Nick and Adam work together. Nick weighs 160 pounds and is gaining about 3 pounds per week. Adam weighs 195 pounds and is losing

Monica [59]

Answer:

160+3x=195-2x

Step-by-step explanation:

So if Nick is 160 lbs and Adam 195, and Nick is gaining 3 pounds per week and Adam is losing 2 pounds per week then you have to use a variable to find the unknown which is the number of weeks. So a gain is positive or addition and a loss is negative of subtraction. Then to solve it put the variables together and the numbers together. The opposite of -2x is 2x so 3x plus 2x and 195 plus the opposite of 160 which is -160 then solve for x.

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3 years ago

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Write an equivalent fraction for each whole number 6

Sidana [21]

3/2 I'm pretty sure that's a correct answer

7 0

3 years ago

What is the greatest possible error for each measurement?

nignag [31]

The greatest possible error of 18.9m is 18.95m - 18.85m = 0.1m

4 0

4 years ago

Read 2 more answers

I need help on two questions!

Inessa05 [86]

1) Answer: $\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

<u>Explanation:</u>

The equation of an ellipse is: $\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$ ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

Center Radius

x-axis: (10 + -10)/2 = 0 10 - 0 = 10

h = 0 a = 10

y-axis: (2 + -2)/2 = 0 2 - 0 = 2

k = 0 b = 2

Now, input the values into the equation:

$\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1$

$\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

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2) Answer: $\frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1$

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1

Center Radius

x-axis: (-1 + 1)/2 = 0 1 - 0 = 1

h = 0 a = 1

y-axis: (1 + -5)/2 = -2 1 - (-2) = 3

k = -2 b = 3

Now, input the values into the equation:

$\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$

$\frac{(x-0)^{2}}{1^{2}} +\frac{(y-(-2))^{2}}{3^{2}} = 1$

$\frac{x^{2}}{1} +\frac{(y+2)^{2}}{9} = 1$

3 0

4 years ago