Question

Write the equation of the line going through the points (-6,3) and (1,11). Write the final equation in slope-intercept form.

Answer 1

This form of straight line is equation through the two points
y - y1 = (y2-y1)/(x2-x1) (x-x1)  point 1(-6,3) and point 2(1,11) => x1= -6, y1= 3, x2=1 and y2= 11 => y- 3 = (11-3)/(1-(-6)) (x-(-6)) => y-3 = 8/(1+6) (x+6) =>
y-3 = 8/7 (x+6) => we will multiply the left and right sides of the equation with number 7 and we get => 7y-21=8(x+6) => 7y-21=8x+48 => we will add to both sides number (+21) => 7y = 8x + 69 => now we will divide the both sides with number 7 => y = (8/7)x+ 69/7 => where 8/7 is coefficient of  direction or (slope) and 69/7 is the cut which this linear function make on the y axis.