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11Alexandr11 [23.1K]
3 years ago
5

Write the equation of the line going through the points (-6,3) and (1,11). Write the final equation in slope-intercept form.

Mathematics
1 answer:
arsen [322]3 years ago
7 0
This form of straight line is equation through the two points
y - y1 = (y2-y1)/(x2-x1) (x-x1)  point 1(-6,3) and point 2(1,11) => x1= -6, y1= 3, x2=1 and y2= 11 => y- 3 = (11-3)/(1-(-6)) (x-(-6)) => y-3 = 8/(1+6) (x+6) =>
y-3 = 8/7 (x+6) => we will multiply the left and right sides of the equation with number 7 and we get => 7y-21=8(x+6) => 7y-21=8x+48 => we will add to both sides number (+21) => 7y = 8x + 69 => now we will divide the both sides with number 7 => y = (8/7)x+ 69/7 => where 8/7 is coefficient of  direction or (slope) and 69/7 is the cut which this linear function make on the y axis.
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Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

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Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

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= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

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