Solution:-
It is given that the points (x,y) be equidistant from the points A(a+b,b-a) and B(a-b,a+b).
PA=PB
Take square both side,
PA^2=PB^2
Now use distance
formula ,
{x-(a+b)}^2+{y-(b-a)}^2={x-(a-b)}^2+{y-(a+b)}^2
=>x^2+(a+b)^2-2x(a+b)+y^2+(b-a)^2-2y(b-a)y=x^2+(a-b)^2-2x(a-b)+y^2+(a+b)^2-2y(a+b)
=>2x(a-b)-2x(a+b)=2y(b-a)-2y(a+b)
=>2x{a-b-a-b}=2y{b-a-a-b}
=>2x(-2b)=2y(-2a)
=>bx=ay
Hence, it is proved.
Answer:
It would look about like this
Step-by-step explanation:
Answer:
<h2>option c.1 /4 ..... totol outcomes =36,,,, favourable outcomes=8,,,,,, probability=8/36====1/4</h2>
The standard equation of a line is y = mx + b thus the final form of the resulting equation should be in this form. Parallel lines are lines with similar or equal slopes (same degree of inclination and direction) so the unknown equation of this line should have a slope of 1/10 as well. To use the point given, another equation form is to be used that is y-y1 = m(x-x1) where (x1,y1) is the point coordinate and m is the slope. Substituting,
y + 7 = 1/10 *(x-4)
Simplifying,
y +7 = 1/10 x - 2/5
y = 1/10 x - 37/5
Multiplying the overall equation by 10,
10 y = x - 74
