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Aleonysh [2.5K]
3 years ago
12

Help with this question please

Mathematics
1 answer:
lilavasa [31]3 years ago
5 0
The answer to this is .64.
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Anyone know how to solve?
sergejj [24]

Answer:

was there more

Step-by-step explanation:

(i will edit answer)

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3 years ago
The base of a triangular pyramid has an area of 20 square feet. The height of the pyramid is 36 feet. The volume of the pyramid
fenix001 [56]

Answer:

so what's the question? i'm a bit confused..

Step-by-step explanation:

7 0
2 years ago
Use the method of completing the square to solve x2 – 8x + 7 = 0. A. x = –5 and x = 13 B. x = 1 and x = 7 C. x = 0 and x = 8 D.
Stolb23 [73]

Answer:

the answe is b (1,7)

Step-by-step explanation:

Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.

x

=

7,1

5 0
3 years ago
Write a subtraction fact with the same difference as 16-7?
Alona [7]
So, this is asking for any number that subtracts to = 16-7

Well, 16-7= 9 so use any two numbers that would subtract to equal 9

Like so:

11-2=9
18-9=9
34-25=9
-2-11=9
Etc....

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0
3 years ago
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