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Tresset [83]
3 years ago
12

How many different three-digit numbers can be written using digits from the set 5, 6, 7, 8, 9 without any repeating digits?

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0
567
598
578
596
597
Keep doing this and you will get your answer. It is could trial and error.
Alina [70]3 years ago
4 0

Answer:

It can be written 60 different three digit numbers.

Step-by-step explanation:

For, calculate how many different three digit numbers can be written, we can use the rule of multiplication as:

<u>     5              </u>* <u>         4        </u> *  <u>           3              </u>  =      60

   1st digit         2nd digit          3rd digit

Taking into account that there is no repeating digits, we have 5 options for the first digits, this options are the number 5, 6, 7, 8 or 9. Then, we have 4 options for the second digit and then we have 3 options for the third digit.

So, there are 60 different three digit numbers that we can create with the set  5, 6, 7, 8, 9 without any repeating digits.

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<span>(243)^(2/5) = ?
---
The 5 in the denominator means "take the 5th root".
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---


</span><span>Taking the 5th root first you get:
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