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Tresset [83]
3 years ago
12

How many different three-digit numbers can be written using digits from the set 5, 6, 7, 8, 9 without any repeating digits?

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0
567
598
578
596
597
Keep doing this and you will get your answer. It is could trial and error.
Alina [70]3 years ago
4 0

Answer:

It can be written 60 different three digit numbers.

Step-by-step explanation:

For, calculate how many different three digit numbers can be written, we can use the rule of multiplication as:

<u>     5              </u>* <u>         4        </u> *  <u>           3              </u>  =      60

   1st digit         2nd digit          3rd digit

Taking into account that there is no repeating digits, we have 5 options for the first digits, this options are the number 5, 6, 7, 8 or 9. Then, we have 4 options for the second digit and then we have 3 options for the third digit.

So, there are 60 different three digit numbers that we can create with the set  5, 6, 7, 8, 9 without any repeating digits.

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What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
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Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

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For x=2,

2y+3(2)=10

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2y=10-6

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Divide both sides by 2.

y=\dfrac{4}{2}

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The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

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A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

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The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

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Multiply both sides by 2.

2(y-15)=-3x

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2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

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