All categories

4 years ago

What point is the center of dilation? point E’ Point H Point O Point G’

Mathematics

2 answers:

swat324 years ago

6 0

Answer:your answer is e my friend

Step-by-step explanation: look for the centure

ExtremeBDS [4]4 years ago

4 0

I am going to say point e but I don’t know

You might be interested in

1. Paula has x cups of food in a container to feed her dogs. She pours 1.5 cups of food into their bowls. There is now 5.25 cups

kifflom [539]

1.D
2.C
3.B
If you need to know the amount let me know.

4 0

3 years ago

The students at Central Elementary School are planning a dinner for their parents.

blsea [12.9K]

They will need 20 pans

5 0

3 years ago

Evaluate 7j+5-8k when j=0.5 and k=0.25

notka56 [123]

Answer:

6.5

Step-by-step explanation:

$7j + 5 - 8k \\ = 7 \times 0.5 + 5 - 8 \times 0.25 \\ = 3.5 + 5 - 2.00 \\ = 8.5 - 2 \\ = 6.5 \\$

5 0

4 years ago

Read 2 more answers

I will mark the brainiest answer if answer is accurate!

Elodia [21]

Answer: The correct answer is Roy

5 0

4 years ago

Read 2 more answers

Given the equation y=14x2−5, the minimum is ___ and the range is ___

mel-nik [20]

Answer:

The minimum is -5

The range is $y \ge -5$

f(14) = 2739

Step-by-step explanation:

Given

$y = 14x^2 - 5$

Solving (a): The minimum

A quadratic function is represented as:

$y = ax^2 + bx + c$

If a > 0, then the function has a minimum

By comparison

$a = 14$ --- the function has a minimum

$b = 0$

$c = -5$

To calculate the minimum, we first calculate the following is calculated as:

$m = -\frac{b}{2a}$

So, we have:

$m = -\frac{0}{2*14}$

$m = 0$

So, the minimum is at f(m)

We have: $y = 14x^2 - 5$

$f(0) = 14 *0^2 - 5$

$f(0) = - 5$

Solving (b): The range

In (a), we have:

$f(0) = - 5$ --- the minimum

This implies that the smallest value of y on the graph is -5.

So, the range is:

$r = \{y|y\ge -5\}$

Solving (c): f(14)

We have:

$y = 14x^2 - 5$

So:

$f(14) = 14 * 14^2 - 5$

$f(14) = 2739$

4 0

3 years ago