<u>Answer</u>
2nd diagram
<u>Explanation.</u>
When contraction a parallel line from a point say N, outside the line, the first thing is to draw a line from point N to the that line.
The point where this line from N intersect with line, name it say P. From this point you can use the properties of angles in a parallel lines to construct the parallel line.
The line NP can act like a transverse of the two parallel lines. The diagram 2 shows first step.
Answer:
48 minutes
Step-by-step explanation:
first divide 6 miles by 2.5 miles, that will be 2.4 miles, then multiply by 20
Answer:
The domain is 
The range is 
Step-by-step explanation:
we have

<em>Find the domain</em>
Remember that
The domain of a function is the set of all possible values of x
we know that the radicand of the function must be greater than or equal to zero
so

solve for x

therefore
The domain is 
<em>Find the range</em>
Remember that
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
For x=7
The value of y is equal to

so
The solution for y is the interval [1,∞)
therefore
The range is 
Answer:
e. 2x - 7y = 31.
Step-by-step explanation:
If you want a line parallel to the equation, the line must have the same slope.
2x - 7y = 9
-7y = -2x + 9
y = 2/7x - 9/7
You are looking for a line where the slope is 2/7.
a. Slope is 7/2.
b. Slope is -7/2.
c. Slope is 7/2.
d. Slope is...
y + 2 = 3/4x + 3
y = 3/4x + 1
Slope is 3/4.
e. Slope is -2/-7, which is 2/7. Just make sure to check whether it passes through (5, -3) by substituting those points into the equation.
2 * 5 - 7 * -3 = 31
10 --21 = 31
10 + 21 = 31
And there's your answer: e.
Hope this helps!
Answer:
- <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>
Explanation
The way each machine works is given by the expression (function) inside it.
<u>1) </u><em><u>Function A</u></em>
To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.
Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.
<u>2) </u><em><u>Function B</u></em>
Solve 
So, he can get an output of 0 by using x = 4.