Diagram the statement three fourths of 40 little engines could climb the hill

For all values of x f(x) = 3x + 2 Find f-¹(-12)

Novosadov [1.4K]

Answer:

-4.67

Step-by-step explanation:

first find f^-1(x)

let f(x)=y

y=3x+2

3x=y-2

x=y-2/3

Therefore f^-1(x)=x-2/3

Now f^-1(-12)=-12-2/3

=-14/3

=-4.67

8 0

2 years ago

Ivy invests $1000 at a simple interest rate of 7%. How much interest will Ivy earn in 3 years * $2100 $70 $210 I don't know

ololo11 [35]

Answer:$210

Step-by-step explanation: 7% of $1000 = $70 x 3yrs =$210

6 0

2 years ago

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

2 years ago

Can someone please help me with this math problem.

mr Goodwill [35]

PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20

d for P₂ = 76 - 82
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20

d for P₂ = 70 - 76
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40

d for P₂ = 70 - 82
d for P₂ = -12

The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.

4 0

3 years ago

I’m wondering how this brainly

Anni [7]

Answer: i dont think so

i mean there arent many bots ive seen at least

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers