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kumpel [21]
3 years ago
7

X+3y=3 2x-4y=6 solve the equations

Mathematics
2 answers:
ankoles [38]3 years ago
7 0
So divide the second equation by 2
x-2y=3
the first equation is
x+3y=3
subsitute
3=3 so therefor
x-2y=x+3y
subtract x from both sides
-2y=3y

add 2y to both sides
0=5y
ofviously y=0 so subsitute
x-2y=3
x-(2)0=3
x-0=3
x=3

x=3
y=0
Gelneren [198K]3 years ago
4 0
Subtract the second equation from double the first equation:

2x+6y-2x-(-4y)=0

10y=0

Therefore, y=0.  Substituting this into the first equation, we see that:

x+3(0)=3

x=3

Therefore, x=3.  The solution to this system is x=3, y=0, or (3, 0).
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