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lys-0071 [83]
2 years ago
15

Distribute and simplify the radicals below.

Mathematics
1 answer:
erastovalidia [21]2 years ago
8 0

The simplified expression of (√12+6)(-√8-√2) is -6√6 - 18√2

<h3>How to simplify the radical?</h3>

The expression is given as:

(√12+6)(-√8-√2)

Factor out -1

(√12+6)(-√8-√2) = -(√12+6)(√8+√2)

Expand the expression

(√12+6)(-√8-√2) = -(√96 + 6√8 + √24 + 6√2)

Evaluate the radicals

(√12+6)(-√8-√2) = -(4√6 + 12√2 + 2√6 + 6√2)

Evaluate the like terms

(√12+6)(-√8-√2) = -(6√6 + 18√2)

Open the bracket

(√12+6)(-√8-√2) = -6√6 - 18√2

Hence, the simplified expression of (√12+6)(-√8-√2) is -6√6 - 18√2

Read more about radicals at:

brainly.com/question/1980062

#SPJ1

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Write the inequality that represents the sentence, ​"Six less than a number is greater than 53​."​
Fiesta28 [93]

Answer:

6<x>53

Step-by-step explanation:

x = number

6 is less than = 6<

greater than 53 = >53

put it all together

6<x>53

4 0
3 years ago
What does the expression “a red rag to the bull” suggest?
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The last resort because you have no more options
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A 6.50% coupon bond with 18 years left to maturity is offered for sale at $1,035.25. What yield to maturity [interest rate] is t
Basile [38]

Answer:

The yield to maturity is 6.3974%

Step-by-step explanation:

The computation of the yield to maturity is as follows

Given that

NPER = 18 × 2 = 36

PMT = $1,035.25 × 6.50% ÷ 2 = $33.65

PV = $1,035.25

FV = $1,000

The formula is shown below:

=RATE(NPER;PMT;-PV;FV;TYPE)

The present value comes in negative

AFter applying the above formula, the yield to maturity is

= 3.1987% × 2

= 6.3974%

Hence, the yield to maturity is 6.3974%

7 0
3 years ago
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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