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lys-0071 [83]
2 years ago
15

Distribute and simplify the radicals below.

Mathematics
1 answer:
erastovalidia [21]2 years ago
8 0

The simplified expression of (√12+6)(-√8-√2) is -6√6 - 18√2

<h3>How to simplify the radical?</h3>

The expression is given as:

(√12+6)(-√8-√2)

Factor out -1

(√12+6)(-√8-√2) = -(√12+6)(√8+√2)

Expand the expression

(√12+6)(-√8-√2) = -(√96 + 6√8 + √24 + 6√2)

Evaluate the radicals

(√12+6)(-√8-√2) = -(4√6 + 12√2 + 2√6 + 6√2)

Evaluate the like terms

(√12+6)(-√8-√2) = -(6√6 + 18√2)

Open the bracket

(√12+6)(-√8-√2) = -6√6 - 18√2

Hence, the simplified expression of (√12+6)(-√8-√2) is -6√6 - 18√2

Read more about radicals at:

brainly.com/question/1980062

#SPJ1

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Step-by-step explanation:

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In y = mx + b form, which is what ur equation is in, the slope can be found in the m position. So the slope of this function is 4.

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slope = (y2 - y1) / (x2 - x1)

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now we sub

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Octagon ABCDEFGH and its dilation, octagon A'B'C'D'E'F'G'H', are shown on the coordinate plane below:
Vaselesa [24]

Answer:

2)  2

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

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The octagon ABCDEFGH has vertices at A(3, 1), B(3, -1), C(1, -3), D(1, -3), E(-3, -1), F(-3, 1), G(-1,3) and H(1, 3)

Octagon ABCDEFGH is then dilated about the origin to form octagon A'B'C'D'E'F'G'H' with vertices at A'(6, 2), B'(6, -2), C'(2, -6), D'(2, -6), E'(-6, -2), F'(-6, 2), G'(-2,6) and H'(2, 6)

A = (3, 1) and A' = (6, 2) = [2(3), 2(1)]

Therefore octagon ABCDEFGH was dilated by a scale factor of 2 to form octagon A'B'C'D'E'F'G'H'

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