The question on the bottom
1 answer:
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The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function
Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2
Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3
From the previous results the correct graph is the last as shown in attached graph.
To find the correct graph, we should study the continuity of the function
Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2
Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3
From the previous results the correct graph is the last as shown in attached graph.
The graph is the one with coordinates (1,2) as the center.
<h3>Answer: Choice D) </h3>
Work Shown:
We must require that and
to avoid having 0 in the denominator. This is why choice D is the answer.