Solve x-y=5 and -3x+2y=-7

Which diagram shows the medians of a triangle? triangle 1 triangle 2 triangle 3 triangle 4

ki77a [65]

Answer————————-triangle 3
Hope this helps!!

4 0

3 years ago

HELP WITH ANY OR ALL THESE PROBLEMS ASAP PLEASE LIKE NOW PLEASE<br>CAN SOMEONE PLEASE HELP

LiRa [457]

Ques 8:

The Volume(V) in cubic feet of an aquarium id modeled by the polynomial function V(x)= $x^{3}+2x^{2}-13x+10$

a) We have to explain that why x =4 is not a possible rational zero.

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

For this , we will substitute the value of x in the given function.

$V(x)=x^{3}+2x^{2}-13x+10$

$V(4)=4^{3}+2(4)^{2}-13(4)+10$

$V(4)=54$ which is not equal to zero.

Therefore, x=4 is not a possible rational zero.

(b) To show that (x-1) is a factor of V(x).

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

Let (x-1)=0

So, x=1.

Substituting x=1 in the given function.

$V(1)=1^{3}+2(1)^{2}-13(1)+10$

$V(1)= -10+10$

V(1) = 0

Therefore, (x-1) is a factor of V(x).

Now we will factorize the given function.

Dividing the given function by (x-1).

On dividing, we get quotient as $x^{2}+3x-10$

So, factored form is = $(x-1)(x^{2}+3x-10)$

= $(x-1)(x^{2}+5x-2x-10)$

= $(x-1)(x(x+5)-2(x+5))$

= $(x-1)(x+5)(x-2)$

(c) So, the dimensions are 1,2 and -5.

5 0

3 years ago

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of pi (no approximations)

Kisachek [45]

Answer:

40π in^2

Step-by-step explanation:

360°/72°=5

so, each of the two shaded regions are 1/5 of the circle.

the formula for finding the area of a circle is πr^2, so:

area for one of the shaded regions:

1/5πr^2

1/5π(10)^2

1/5π100

20π in^2

this means that the area for one of the shaded regions is 20π. however, since there are two of them:

2(20π)=40π

so, the area of the shaded regions is 40πin^2

5 0

3 years ago

Is 15 to 35 and 27/66 equivalent

Alex777 [14]

The two ratios are not equivalent

3 0

3 years ago

Read 2 more answers

Some girls in a Girl Scout troop are pairing up with some boys in a Boy Scout troop to practice square dancing. Two-thirds of th

Natalka [10]

Answer:

Fraction of the scouts are square dancing is $\frac{19}{30}$ .

Step-by-step explanation:

Each pair is one Girl Scout and one Boy Scout.

So, to the final fraction ( of the pairs) we are going to get 1/2 from the fraction of girls and 1/2 from the fraction of boys.

Girls= $\frac{2}{3} *\frac{1}{2} =\frac{2}{6}$

Boys= $\frac{3}{5} *\frac{1}{2} =\frac{3}{10}$

To get the fraction of the scouts that are square dancing, we have to add the fraction of girls , with the fraction of boys.

= $\frac{2}{6} +\frac{3}{10}$

= $\frac{(2*10) +(6*3)}{6*10} =\\ \frac{20+18}{60}$

= $\frac{38}{60}$

= $\frac{19}{30}$

This means that from 30 scouts , 19 are dancing.

5 0

3 years ago