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saw5 [17]
3 years ago
12

Mr Floyd is laying grass squares in his backyard. He will cover the entire yard except for the vegetable garden. How many square

feet of grass will be used? The length is 25 and the width is 15. the garden is 8ft by 8 ft
Mathematics
2 answers:
Gwar [14]3 years ago
6 0
En total utilizaría 25

Alenkasestr [34]3 years ago
3 0

Here we can first find the area of yard and then subtract the area of vegetable garden to get the required area.

The formula to find area is given by:

A = l* w

Now we find area of yard:

length is 25 ft and width is 15 ft.

A = 25 * 15

Area of yard = 375 ft²

Area of vegetable garden:

length = 8ft and width =8ft

So the vegetable garden is a square.

Area = 8*8

Area of vegetable garden =64 ft²

Area of backyard to be laid with grass = Area of yard-Area of vegetable garden

Area required = 375 -64 = 311 ft²

Answer : The area of backyard in which grass is to be laid is 311 square feet.

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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

x=(7)+(-4)t

x=7-4t

Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

5 0
3 years ago
10 Pts <br> Multiplying fractions:<br><br> 5     1 <br> — x — = <br> 6     2
Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}

\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}

\dfrac{5}{6} \times \dfrac{1}{2} = \dfrac{5 \times 1}{6 \times 2} = \dfrac{5}{12}

6 0
3 years ago
Read 2 more answers
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PSYCHO15rus [73]
The answer is sixteen 1.25 ÷ 20 = 16
4 0
3 years ago
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1000 was invested at 5.5% interest, compounded annually. After sometime the amount had grown to 1550. How long was the money inv
scZoUnD [109]

compound interest equation for annually compounded

A=P(1+r)^t

A=final amount

P=principal

r=rate in decimal

t=time in years


given that

A=1550

P=1000

r=5.5%=0.055

find t


1550=1000(1+0.055)^t

divide both sides by 1000

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take ln of both sides

ln(1.55)=ln(1.055^t)

use ln rule ln(a^b)=b(ln(a))

ln(1.55)=t(ln(1.055))

divide both sides by ln(1.055)

\frac{ln(1.55)}{ln(1.055)}=t

using a calculator, we get that t=8.18544 yrs

so about 8.2yrs

4 0
2 years ago
Use the table below to answer this question:
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In the interval from x=-1 to x=2, x increases by 3. In that same interval, y increases by 6 from -3 to +3. The average rate of change is
.. average rate of change = (increase in y)/(increase in x) = 6/3 = 2

The average rate of change is 2 over the given interval.
8 0
3 years ago
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