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kap26 [50]
3 years ago
8

The manager at Food Town estimates that the store sold 325 jars of spaghetti sauce last week. The store actually sold 297 jars o

f spaghetti sauce. What is the manager’s percent error?
Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer: 9.43%

Step-by-step explanation:

The formula to calculate the percent error is given by :-

\% \text{ error}=\dfrac{|\text{Estimated value - Actual value}|}{\text{Actual value}}}\times100

Given : The manager at Food Town estimates that the store sold 325 jars of spaghetti sauce last week. The store actually sold 297 jars of spaghetti sauce.

i.e.  Estimated value = 325

Actual value = 297

Then , the percentage error would be :-

\% \text{ error}=\dfrac{|325-297|}{297}\times100\\\\=\dfrac{|28|}{297}\times100\\\\=\dfrac{28}{297}\times100=9.42760942761\approx9.43\%

hence, the manager’s percent error is approximately 9.43% .

never [62]3 years ago
5 0

There is a positive, linear relationship between the correct and guessed calories. The guessed  calories for 5 oz. of spaghetti with tomato sauce and the cream-filled snack cake are unusually  high and do not appear to fit the overall pattern displayed for the other foods.  The correlation is r = 0.825 . This agrees with the positive association observed in the plot; it is not closer to 1  because of the unusual guessed calories for spaghetti and cake.  The fact that the guesses are  all higher than the true calorie count does not influence the correlation. The correlation r would  not change if every guess were 100 calories higher. The correlation r does not change if a  constant is added to all values of a variable because the standardized values would be unchanged.  The correlation without these two foods is r = 0.984 . The correlation is closer to 1 because  the relationship is much stronger without these two foods.

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Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

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3 years ago
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Answer:

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Step-by-step explanation:

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Melanie eats 1.5 pounds of cereal each week. Which model below best represents the number of pounds of cereal she eats in .5 wee
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For this case, the first thing we must do is define a variable.
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 y: amount of cereal that Melanie eats
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A model that best represents the number of pounds of cereal she eats is:
 
y = 1.5x&#10;
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y = 7.5 pounds
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Step-by-step explanation:

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3 years ago
Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale
valkas [14]

Answer:

The specific weight is 1.5\frac{g}{cm^{3}}

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=255\pi\ cm^{2}

l=17\ cm

substitute the values

255\pi=\pi r(17)

Simplify

255=r(17)

r=255/(17)=15\ cm

step 2

Find the height of the cone

Applying the Pythagoras Theorem

l^{2} =r^{2} +h^{2}

substitute the values and solve for h

17^{2} =15^{2} +h^{2}

h^{2}=17^{2}-15^{2}

h^{2}=64

h=8\ cm

step 3

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

substitute the values

V=\frac{1}{3}\pi (15)^{2}(8)

V=600\pi\ cm^{3}

step 4

Find the specific weight

Divide the mass by the volume

\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}

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3 years ago
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