All categories

3 years ago

Write as a mixed number 5.06

Mathematics

2 answers:

Olegator [25]3 years ago

6 0

Answer:

5 $\frac{3}{50}$

Step-by-step explanation:

sleet_krkn [62]3 years ago

3 0

Answer:

5 $\frac{3}{50}$

Step-by-step explanation:

0.06 = 6/100 = 3/50

You might be interested in

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

MAXImum [283]

<span>f(k) = k2 + 2k + 1 = (k+1)^2
The range is what the function gives to you f(k)=25=5^2 or (-5)^2
f(k)=64=8^2 or (-8)^2

You need to find the k values for these boundary values to find the domain.
Good luck :)</span>

7 0

3 years ago

3y^4+9y^3-120y^2=0 Need Answer ASAP

Shkiper50 [21]

Answer:

y = 0 , 5 , − 8

(*￣3￣)╭

7 0

3 years ago

Read 2 more answers

Is a parallelogram an equilateral?

Vladimir [108]

"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."

4 0

3 years ago

What is a 3-dimensional shape made of two identical circles connected by a rectangle

nekit [7.7K]

Answer:

cylinder

Step-by-step explanation:

5 0

3 years ago

In in the previous activity you solved a system of equations representing the carnival admissions using the elimination method i

Mariulka [41]

Answer:

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 $k+a=500$ both variables k has 1 as their coefficient.

Step-by-step explanation:

We need to solve the system of equations using substitution method

The equation are:

$k + a = 500--eq(1)\\3k + 10a = 3,600 --eq(2)$

For substitution method, we find value of k from equation 1 and put in equation 2

$From \ eq(1) \ we \ get\\k=500-a$

Putting it in eq(2)

$3k+10a=3600\\Put \ k=500-a\\3(500-a)+10a=3600\\1500-3a+10a=3600\\7a=3600-1500\\7a=2100\\a=\frac{2100}{7}\\a=300$

So, we get value of a = 300

Now finding value of k by putting value of a in equation $k=500-a$

$k=500-a\\Putting \ a \ =500\\k=500-300\\k=200$

So, we get value of k =200

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 $k+a=500$ both variables k has 1 as their coefficient.

4 0

3 years ago