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leva [86]
4 years ago
5

Can someone help me with this please I would really appreciate it

Mathematics
1 answer:
mart [117]4 years ago
5 0
21-3x=2x+1
Get the variable on one side
-5x=20
20/5
The answer is 4
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Factor the expression <br> 36s^2-25
Snowcat [4.5K]

Answer:

(6x + 5) • (6x - 5)

Step-by-step explanation:

36x2-25

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (22•32x2) -  25

Step  2  :

Trying to factor as a Difference of Squares :

2.1      Factoring:  36x2-25

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  36  is the square of  6

Check : 25 is the square of 5

Check :  x2  is the square of  x1

Factorization is :       (6x + 5)  •  (6x - 5)

Final result :

 (6x + 5) • (6x - 5)

8 0
3 years ago
Judah is going to deposit $5,000 in an account that earns 4% interest for 20 years. How much more interest will he earn if the a
Anna71 [15]

Answer:

If the account earns annual compound interest rather than annual simple interest, the account earns extra $1955.62

Step-by-step explanation:

Given :

Principal amount P = $5000

Annual interest rate r = 4% = 4/100 = 0.04

time t = 20 years

First we have to calculate account balance when account earns annual simple interest. We know that the formula is

A = P(1+rt)

   = 5000 (1+ (0.04 x 20))

   = 5000 (1.8)

   = 9000

Interest earned for annual simple interest = 9000 - 5000

                                                                        = 4000

Now we will calculate account balance when account earns annual compound interest. The formula is

A = P(1 + \frac{r}{n} )^{nt}

Since here interest is compounded annually, n =1, hence we get

A = P(1+r)^{t}

   = 5000 (1+0.04)^{20}

   = 10955.62

Interest earned for annual compound interest = 10955.62 - 5000

                                                                                = 5955.62

The extra interest earned = 5955.62 - 4000

                                          = 1955.62

Hence f the account earns annual compound interest rather than annual simple interest, the account earns extra $1955.62

6 0
4 years ago
Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office?
RideAnS [48]

This question is incomplete and it also lacks an attached diagram.

Find attached to this answer the appropriate diagram.

Complete Question:

The conditional relative frequency table was generated using data that compared the cost of one ticket for a performance and the method by which the ticket was purchased.

Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office? Express the answer in decimal form

Answer:

0.14

Step-by-step explanation:

From the attached diagram, we were given a table that contained known values:

The number of tickets that were purchased online we have 2 categories

a) Not more than $30 = 0.7

b) More than $30 = 0.86

The number of tickets that were purchased at the box office also had 2 categories.

a) Not more than $30 = 0.3

b) More than $30 = 0.14

The probability that the ticket Lorenzo paid more than $30 for was purchased at the box office

= P( more than $30 at the box office)

= 0.14

6 0
4 years ago
The table below shows the different combinations of honey and oats that can be used in making granola.
posledela

Answer:

C

Step-by-step explanation:

PLEASE MARK BRAINLIEST

8 0
3 years ago
Read 2 more answers
In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0
3 years ago
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