Answer:
this picture on my end its a little blury
Answer:
![2,25[-3 + x]](https://tex.z-dn.net/?f=2%2C25%5B-3%20%2B%20x%5D)
Step-by-step explanation:
The Greatest Common Divisor [GCD] is 2,25; you factor that out, leaving the remaining result inside the brackets.
I am joyous to assist you anytime.
Answer:
65 mili= 6.5cm
Step-by-step explanation:
divide the length value by 10
Answer:
x = 14
Step-by-step explanation:
Given
-
(x - 4) = - 2
Multiply both sides by 5 to eliminate the fraction
- (x - 4) = - 10 ← distribute parenthesis by - 1
- x + 4 = - 10 ( subtract 4 from both sides )
- x = - 14 ( multiply both sides by - 1 )
x = 14
Answer:

Step-by-step explanation:
Given,
Angle of sector = 30°
Radius of circle, r = 8 cm
Area of the shaded region, A =?
The diagram is attached below.
Now,
Area of shaded region = Area of sector - Area of triangle
Area of triangle = 
We know that,




And




Area of sector = 
Area of sector = 
= 16.75 cm^2
Area of triangle = 
= 13.85 cm^2
Area of shaded region = 16.75 - 13.85
= 