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max2010maxim [7]

3 years ago

14

Plz help me, T-T I really need this is for class

1 answer:

vekshin13 years ago

4 0

Answer:

Ask: To check and make sure your answer is correct

Share: Subtracting a number is the same as adding its opposite. So, subtracting a positive number is like adding a negative; you move to the left on the number line. Subtracting a negative number is like adding a positive; you move to the right on the number line.

Step-by-step explanation:

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Write this number in standard form.<br> 1.498 x 10² = [? ]

ch4aika [34]

149.8

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2 years ago

Ratio for 6 cups and it serves 28

Sophie [7]

Cups 6 3
servings 28 14

Therefore the ratio to cups to servings is 3/14

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3 years ago

Solution or not a solution<br><br> and because

tamaranim1 [39]

Step-by-step explanation:

X + Y = -3

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3 years ago

U-substitutions only work for specific kinds of expressions. Below, you are asked to choose a value of n for which u-substitutio

Dahasolnce [82]

Answer:

Step-by-step explanation:

(a) $\int x^n e^{5x^4+1} \ dx$

Suppose $5x^4 + 1 = f$

by differentiation;

$\implies \ 20 x^3 dx = df --- (1)$

Suppose n = 3

Then, the integral

$I = \int x^ 3 e^{5x^4 + 1} \ dx$

$= \int e^f \ \dfrac{df}{20}$

$= \dfrac{1}{20} \int e^f \ dt$

$= \dfrac{1}{20} e^f + C$

recall that $f = 5x^4 + 1$

Then;

$\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}$

(b) $\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx$

suppose; $\dfrac{1}{x^3} = f$

$x^3 = f$

$\implies -3x^{-4} \ dx = df$

$\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df$

If n = u, then the integration is:

$I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx$

$= \int -\dfrac{1}{3} \ cos \ f \ df$

$= -\dfrac{1}{3} \int \ cos \ f \ df$

$= -\dfrac{1}{3} \ sin \ f + C$

Since; $x^3 = f$

Then;

$\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}$

(c) $\int \dfrac{x+n}{x^2 + 8x -4} \ dx$

Suppose $x^2 + 8x - 4 = f$

Then, by differentiation of both sides

$(2x + 8) \ dx = df$

$(x + 4) \ dx = \dfrac{1}{2} \ df$

Suppose n = 4 in integration, then:

$I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx$

By substitution;

$I = \int \dfrac{1}{2}\dfrac{1}{f} \ df$

$= \dfrac{1}{2} \ \ { In |f|} + C$

$\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}$

7 0

3 years ago

how to use the explicit formula an=a1+(n-1)d to find the 500th term of the sequence 24,30,36,42,48,...

Leni [432]

A1=24
<span>n=500(seq #) </span>
<span>d=how much u add each time=6 </span>

<span>a(n)=24+(500-1)(6)=3018</span>

7 0

3 years ago

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