Answer:C
Step-by-step explenation: m=134kg,h=72m,g=10m/s
PE=mgh
PE=(134kg)(10m/s^2)(72m)
PE=964800J
If this was a cone, the volume would be 314.16.
- You would just put in the radius and height in the cone volume formula which is πr²h 1/3
If this is a cylinder then the volume would be 942.48
- Put in the radius and height in the cylinder volume formula which is πr²h
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
b
Step-by-step explanation:
all you do is divide 10.2 by tan (67) and you get 4.33
