This is a proportion problem because the problem stated that the two team pennants are similar.
Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base = 6 in ; length = x ?
9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x
The length of the side of the smaller pennant is 3 inches.
X=-1.5. this is the axis of symmetry. (-b/2a) then plug in this value to find the vertex
A = LW
LW = A
(x + 3)(x - 8) = 42
x^2 - 8x + 3x - 24 = 42
x^2 - 5x - 66 = 0
(x - 11)(x + 6) = 0
x - 11 = 0 or x + 6 = 0
x = 11 or x = -6
The length of the side of a rectangle cannot be a negative number, so we discard the negative answer, x = -6.
Answer: x = 11
Radius of cone = 4/2 = 2 in
height os cone = sqrt(6^2 - 2^2) = sqrt(36 - 4) = sqrt(32)
Volume of cone = 1/3pi r^2 h = 1/3 x 3.14 x 2^2 x sqrt(32) = 23.7 cubic inches.
Answer:
84in²
Step-by-step explanation:
this is very easy
