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icang [17]
3 years ago
9

Solve for p in the literal equation 8p+5r=q

Mathematics
1 answer:
matrenka [14]3 years ago
3 0
Subtract by 5r and divide by 8 to isolate p, p=(q-5r)/8
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I don't understand this class and my teacher is stupid and won't go over it again to help me better understand​
allochka39001 [22]

Answer:

Well i believe the answer is obtuse

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. Solve the following<br> system:<br> 2x + 2y = 38<br> y = x + 3
pashok25 [27]

Answer:

y=11

x=8

Step-by-step explanation:

This is Elimination

2x+2y=38

Subtract 2x on both sides   2y=-2x+38

Then Multiply 2(y=x+3)  which equals 2y=2x+6

Solve by Elimination

2y=-2x+38

2y=2x+6

add the y's and since the x's are different those cancel out, then add 38 and 6.

then you do the equation 4y=44

divide both by 4

y=11

then you do 11=x+3

subtract 3 on both sides

x=8

and there you go

I hope this is how you wanted it solved

4 0
4 years ago
Pedro's Diner is open six days a week. His income for the first five days this week was
AnnZ [28]

Pedro must make $330 on the 6th day to have a mean average of $200.

Step-by-step explanation:

<u>Formula for Mean Average</u>

Mean Average = \frac{Sum of data}{Total number of data}

<u>DATA:</u>

1st day = $120

2nd day = $110

3rd day = $200

4th day = $300

5th day = $140

6th day = x

<u>Solution:</u>

Mean Average = \frac{Sum of data}{Total number of data}

200 = \frac{120+110+200+300+140+x}{6}

200*6 = 870+x

1200 - 870 = x

x = 330

Pedro must make $330 on the 6th day to have a mean average of $200.

Keyword: Mean

Learn more about mean at

  • brainly.com/question/5069437
  • brainly.com/question/6073431

#LearnwithBrainly

6 0
3 years ago
Find the range of 5,3,1,1,3,3,4,4,4,1,1,4,2,2,5,5,5,2,5,5​
ExtremeBDS [4]
Answer: 4

find the largest number (5) and take away the smallest (1)

5-1=4
6 0
3 years ago
Find f(x+2) of the function f(x)= 4x^2+2x-4 HELP ASAP PLEASE WORTH 40 POINTS
nata0808 [166]

Answer:

The functional expression can be simplified by substituting the given value in the function in place of the variable.

For example, if {eq}f(x)=x^{2} {/eq} be a function then {eq}f(2) {/eq} is determined by plugging {eq}x=2 {/eq} in the function.

Step-by-step explanation:

The given function is:

{eq}f(x) = 4x^{2} + 2x {/eq}

Let {eq}y=\frac{f(x + h) - f(x)}{h} {/eq} then we have:

{eq}\\\\\begin{align*} y & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} \\\\ & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} \\\\ & = \frac{4(x^{2}+2xh+h^{2}) + 2x+2h-4x^{2}-2x}{h} \\\\ & = \frac{4x^{2}+8xh+4h^{2}+ 2h-4x^{2}}{h} \\\\ & = \frac{8xh+4h^{2}+ 2h}{h} \\\\ & = \frac{h(8x+4h+2)}{h} \\\\ & = 8x+4h+2 \\\\\end{align*} {/eq}

7 0
3 years ago
Read 2 more answers
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