Ask question

Ask question

All categories

2 years ago

12

If an ordered pair was added to the table, which of the following pairs would result in the table becoming not a function. (-3,

6) (0, 8) (3, 20) (8, 4) (-10, 8)
(A) (– 8, 8) (C) (8, 3) ( B) (6, 3)(D) (– 3, 4)
help please

1 answer:

frosja888 [35]2 years ago

8 0

Answer:

the answer is a I just took the test and its right

Step-by-step explanation:

You might be interested in

Solve for m and b <br><br>(5,14) and (3,10)

Elis [28]

Y=mx+b

Y1-Y2/X1-X2

14-10/5-3 = 4/2 = 2

Plug in (3,10):
(10)=2(3)+b

Solve:
10=6+b

B=4
M=2

6 0

2 years ago

If there are four quarters in a dollar, which expression correctly shows how you might figure out how many quarters are in $9.25

xxMikexx [17]

Answer:

37

Step-by-step explanation:

4(9) + 1 = 37

7 0

2 years ago

Read 2 more answers

For what values of a are the following expressions true?/a+5/=-5-a

katovenus [111]

Explanation:

The expression is given below as

$|a+5|=-5-a$

Concept:

We will apply the bsolute rule below

$\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}$

By applying the concept, we will have

$\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}$

Hence,

The final answer is

$a\leq-5$

5 0

6 months ago

A bag of marbles has 6 red marbles and 7 green marbles in it. What is the percent probability of pulling a green marble out of t

soldi70 [24.7K]

Answer:

If a bag contains 4 red marbles, 3 blue marbles, and 7 green marbles and a marble is randomly selected from the bag, what is the probability that it is blue? P=3/(3+4+7)=3/14 because each of 14 marbles is equally likely to be drawn.

Step-by-step explanation:

7 0

3 years ago

How many variable terms are in the expression 3x3y + 5xz − 4y + x − z + 9?

Dimas [21]

Answer:

3

Step-by-step explanation:

there are only x y and z used in the expression no matter how many times they multiply.

8 0

2 years ago