Answer:
idk im dumb
Step-by-step explanation:
It can be or it depends on how the equation is set up
We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
Answer:
a) Put x=10, then the both terms will be same.
b) (2x+3) and 23
c) (2x+3) is a general term for all values of x and 23 is a particular value for x=10
Step-by-step explanation:
a) Considering the following two fractions (4x²+8x+3)/(2x+1) and 483/21, they are equivalent to each other for the value of x =10.
Therefore, if you put x=10 in the fraction (4x²+8x+3)/(2x+1), then it will become 483/21. (Answer)
b) The quotient of the fraction (4x²+8x+3)/(2x+1) will be obtained by as follows:
(4x²+8x+3)/(2x+1) {By factorizing the numerator}
=(4x²+6x+2x+3)/(2x+1)
=(2x+3)(2x+1) / (2x+1)
=2x+3
Again, the quotient of the fraction 483/21 =23 (Answer)
c) Again, if you put the value of x =10 in the quotient (2x+3), then it will result 23. Therefore, (2x+3) is a general term which is valid for all the real values of x and 23 is a particular value for x=10. (Answer)
Answer: D
Step-by-step explanation: X is positive and Y Has some negative but the same numbers.
