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Anit [1.1K]
3 years ago
10

Jill has 3/4 of a yard of ribbon. Tammy has 4/7 of a yard. how much do they have together?

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
37/28 or 1and9/28 you have to find the common denominator
natulia [17]3 years ago
3 0
3/4+4/7
12/28+16/28
28/28= 1

they  has one full ribbon. hope its right
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The temperature at noon on a winter day was 8°C. At midnight, the temperature had dropped 15°C. What was the temperature at midn
klio [65]
All you have to look at is the word "dropped" and you know it's a subtraction problem. In this case, it would be 8 - 15.

8 - 15 = -7

It would be -7<span>°C at midnight. I hoped this helped! :)</span>
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Step-by-step explanation:

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Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
3 years ago
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