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alexandr1967 [171]

3 years ago

6

Plz, the question is below!

2 answers:

gulaghasi [49]3 years ago

4 0

it would be trapezoid

Andreyy893 years ago

4 0

Answer:

it would be trapezoid

Step-by-step explanation:

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Whats 2 plus 2? Whats 10 plus 10? And whats 8 plus 8?

Ivenika [448]

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Whats 2 plus 2?
$\boxed{2+2=4}$
Whats 10 plus 10?
$\boxed{10+10=20}$
And whats 8 plus 8?
$\boxed{8+8=16}$

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2 years ago

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What is the side length of a 121 square centimeter launch pad

DIA [1.3K]

11 centimeters is the length of the launch pad

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3 years ago

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Need help solving hi

steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

$2 \ln(x+2)=6$

$\ln (x+2)=3$

$e^{\ln(x+2)}=e^3$

$x+2=e^3$

$x=e^3-2$

$x\approx 18. 09$

8 0

2 years ago

Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0

2 years ago

Hellllpppppppppppppp

alexandr402 [8]

It should be 54 because height times width

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2 years ago