$\it \mathcal{V} =\dfrac{\mathcal{A}_b\cdot h}{3} \Rightarrow h = \dfrac{3\mathcal{V}}{\mathcal{A}_b}= \dfrac{3\cdot3072}{\mathcal{A}_b}\ \ \ \ \ (*)
\\\;\\ \\\;\\
\mathcal{A}_b = \dfrac{\ell^2\sqrt3}{4} = \dfrac{16^2\sqrt3}{4} =\dfrac{16\cdot16\sqrt3}{4} =4\cdot16\sqrt3=64\sqrt3\ \ \ \ (**)
\\\;\\ \\\;\\
(*),\ (**) \Rightarrow h=\dfrac{3\cdot3072}{64\sqrt3} = \dfrac{3\cdot48}{\sqrt3} = \dfrac{\sqrt3\cdot\sqrt3\cdot48}{\sqrt3} = 48\sqrt3\ inches$

4 0

2 years ago

1) (x+y)² =<br>A. x²+2xy+y²<br>B. x²-2xy+y²<br>C.x²-2xy-y²

olchik [2.2K]

Answer:

a. x^2+2xy+y^2

Step-by-step explanation:

I hope this helps

8 0

2 years ago

Read 2 more answers

If 7 of the same books cost £84, how many can be brought for £48