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Mkey [24]
3 years ago
9

How do you answer this

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
you just need to multiply the length times width
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Solve for v 2(3v+8)=70
yuradex [85]

Answer:v = 9

Step-by-step explanation:

Simplifying

2(3v + 8) = 70

Reorder the terms:

2(8 + 3v) = 70

(8 * 2 + 3v * 2) = 70

(16 + 6v) = 70

Solving

16 + 6v = 70

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-16' to each side of the equation.

16 + -16 + 6v = 70 + -16

Combine like terms: 16 + -16 = 0

0 + 6v = 70 + -16

6v = 70 + -16

Combine like terms: 70 + -16 = 54

6v = 54

Divide each side by '6'.

v = 9

5 0
3 years ago
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Help me please (I need write more something in order to I can submit answer)​
Nataly_w [17]

Answer:

The answer is 4

Step-by-step explanation:

(-2.4)(10) / -3(2)

-24/-6

=4

8 0
2 years ago
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BRAINLIEST!!!
Nutka1998 [239]

Answer:

\frac{35}{48}

Step-by-step explanation:

Probability:Probability=\frac{favourable\ outcome}{total\ outcome}

Probability of NOT 6:

Total\ outcomes=\{1,2,3,4,5,6\}\\\\Number\ of\ total\ outcomes=6\\\\Favourable\ Outcomes= NOT\ 6=\{1,2,3,4,5\}\\\\Number\ of\ favourable\ outcomes=5\\\\P(NOT\ 6)=\frac{5}{6}

Probability of NOT H:

Total\ outcomes=\{A,B,C,D,E,F,G,H\}\\\\Number\ of\ total\ outcomes=8\\\\Favourable\ Outcomes= NOT\ H=\{A,B,C,D,E,F,G\}\\\\Number\ of\ favourable\ outcomes=7\\\\P(NOT\ H)=\frac{7}{8}

Probability of NOT 6 and NOT H:

Both\ events\ are\ independent\\\\P(NOT\ 6\ and\ NOT\ H)=P(NOT\ 6)\times P(NOT\ H)\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{5}{6}\times \frac{7}{8}\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{35}{48}

6 0
3 years ago
If two angles are ​complementary ​angles and they measure m​ ∠1=(x + 5)​ and ​m∠2=(5x + 13)​. Find x and the measure for both an
Korolek [52]

<em>5</em><em>X</em><em>+</em><em>1</em><em>3</em><em>+</em><em>X</em><em>+</em><em>5</em><em>=</em><em>9</em><em>0</em><em>°</em><em>(</em><em>SUM</em><em> </em><em>OF</em><em> </em><em>COMPLEMENTRY</em><em> </em><em>ANGLE</em><em> </em><em>IS</em><em> </em><em>EQUAL</em><em> </em><em>TO</em><em> </em><em>9</em><em>0</em><em>°</em><em>)</em>

<em>6</em><em>+</em><em>1</em><em>8</em><em>=</em><em>9</em><em>0</em><em>°</em>

<em>6</em><em>X</em><em>=</em><em>9</em><em>0</em><em>°</em><em>-</em><em>1</em><em>8</em><em>°</em>

<em>X</em><em>=</em><em>7</em><em>2</em><em>°</em><em>/</em><em>6</em>

<em>X</em><em>=</em><em>1</em><em>2</em><em> </em><em>°</em><em>ANSWER</em>

6 0
3 years ago
A bag holds 1 blue block and 3 yellow blocks. How many green blocks should be added to the bag to make the probability of random
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n - the number of green blocks which is equal to the number of favourable events
1+3+n=4n - the number of all blocks, which is equal to the number of all possible outcomes

P(A)=\dfrac{n}{4+n}=\dfrac{1}{2}\\&#10;1\cdot( 4+n)=2\cdot n\\&#10;4+n=2n\\&#10;2n-n=4\\&#10;n=4&#10;
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