So, let's look at the problem once again.
8%, or 8/100 of the bag were green jelly beans.
Let's see what we can do to find out a number of other jelly beans, not including the green ones.
We know that 92% of jelly-beans are not green.
92% is 11.5 times more than 8%
(92/8)
24 (or 8%) times 11.5 = 276
276 - number of jelly beans that are not green.
276 plus 24 = 300.
Answer: 300 jelly beans were in one bag.
For this case we have that by definition, the volume of a cube is given by:
Where:
l: It's the side of the cube
According to the statement data:
Substituting in the formula we have:
Thus, the shipping cube volume is
Answer:
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Well i’m not sure on this but i got 18 for my answer instead of 10 so if u need any mode help im here
The order will be IV, III, I, and II.
<h2>Polynomial</h2>
Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.
Given
I. x + 2xyz
II. 9x³y²
III. 18x² + 5ab - 6y
IV. 4
+ 3x² - x - 4
<h3>To find </h3>
The polynomial expressions from least to greatest are based on their degree.
<h3>How to organize?</h3>
4 + 3x² - x - 4 is a biquadratic ploynolmial.
18x² + 5ab - 6y is a cubic polynomial.
x + 2xyz is a quadratic polynomial.
9x³y² is a monomial polynomial.
So the order will be IV, III, I, and II.
More about the polynomial link is given below.
brainly.com/question/17822016
