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2 years ago

a playground is 750 M long and 250 m broad find the cost of levelling at rupees 16 per 100 square metres

Mathematics

1 answer:

barxatty [35]2 years ago

4 0

Answer:

Area of play ground = Length × Breadth = 750 × 250 = 187500. a Cost of levelling the ground = 187500 × 16 100 = Rs . 30000

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Tamara earns 2,050 every month. She spends 65% on the amount that she earns. The rest of the money is equally divided and deposi

victus00 [196]

Answer:

Tamara earns $2,050 each month.

She spends 65% of that, so the amount that she spends is:

S = (65%/100%)*$2,050 = 0.65*$2,050 = $1,332.50

Then the amount that she has left is:

R = $2,050 - $1,332.50 = $717.50

Now she divides that in half, and deposits those amounts in two separate accounts.

She deposits $717.50/2 = $358.75 in each acount.

Then she deposits $358.75 per month, so after x months she has:

x*$358.75 in each of those accounts, so one of the accounts will have more than $2,500 when:

x*$358.75 = $2,500

x = $2,500/$358.75 = 6.96

So after 6.96 moths she will have more than $2,500 in one of her accounts, we can round it to:

After 10 months Tamara has deposited more than 2,500 in one of her accounts.

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3 years ago

Factorise the following:<br> c) x - 3x + 2

fenix001 [56]

Answer:

2 ( - x + 2 )

Step-by-step explanation:

x - 3x + 2 = - 2x + 2

- 2x = 2 * - x

2 = 2 * 1

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Hence factorized.

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2 years ago

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Find two numbers with a sum of 20 and a difference of 14

shepuryov [24]

2 and 7 r the answer

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3 years ago

2t - 5 = -10 what is t

jenyasd209 [6]

The answer is -.2.5 hope that help

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3 years ago

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Working together to palms can drain a certain pool in three hours if it takes the older pump nine hours to drain the pool by its

andreyandreev [35.5K]

Answer:

It would take the newer pump 4.5 hours to drain the pool

Step-by-step explanation:

Let's investigate first what is the fraction of the job done in the unit of time (hour in this case) by each pump if the work individually:

older pump: if it takes it 9 hours to complete the job, it does $\frac{1}{9}$ of the job in one hour.

newer pump: we don't know how long it takes (this is our unknown) so we call it "x hours". Therefore, in the unit of time (in one hour) it would have completed $\frac{1}{x}$ of the total job.

both pumps together: since it takes both 3 hours to complete the job, in one hour they do $\frac{1}{3}$ of the job.

Now, we can write the following equation about fractions of the job done:

<em>The fraction of the job done by the older pump plus the fraction of the job done by the newer pump in one hour should total the fraction of the job done when they work together.</em> That is in mathematical terms:

$\frac{1}{9} +\frac{1}{x} =\frac{1}{3}$

and solving for x:

$\frac{1}{9} +\frac{1}{x} =\frac{1}{3} \\x+9=3x\\2x=9\\x=\frac{9}{2} \,\,hours\\x = 4.5\,\,hours$

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3 years ago

a playground is 750 M long and 250 m broad find the cost of levelling at rupees 16 per 100 square metres​

a playground is 750 M long and 250 m broad find the cost of levelling at rupees 16 per 100 square metres