Answer: With that assumption, we have a square, whose area is given by the formula Asquare=a2, and two semicircles. The distance D is simply the square's diagonal. The area of each semicircle is given by the formula Asemicircle=π*r2/2. then you will get your answer!
Answer:
5.517miles/min
Step-by-step explanation:
331/1h
=331/(1*60) because 1h=60min
Answer:
1. reflection across x-axis
2. translation 6 units to the right and 3 units up (x+6,y+3)
Step-by-step explanation:
The trapezoid ABCD has it vertices at points A(-5,2), B(-3,4), C(-2,4) and D(-1,2).
First transformation is the reflection across the x-axis with the rule
(x,y)→(x,-y)
so,
- A(-5,2)→A'(-5,-2)
- B(-3,4)→B'(-3,-4)
- C(-2,4)→C'(-2,-4)
- D(-1,2)→D'(-1,-2)
Second transformation is translation 6 units to the right and 3 units up with the rule
(x,y)→(x+6,y+3)
so,
- A'(-5,-2)→E(1,1)
- B'(-3,-4)→H(3,-1)
- C'(-2,-4)→G(4,-1)
- D'(-1,-2)→F(5,1)
Answer:
6^2
Step-by-step explanation:
We know a^b / a^c = a^(b-c)
6^5 / 6^3 = 6^(5-3) = 6^2
The height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.
<h3>What is trigonometry?</h3>
Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
We have:
Angle = 71 degree
Distance between A and B = 20 meters
Let's suppose the height of the building is x meters.
From the right angle triangle applying the tan ratio:
tan71 = x/20
x = 58.08 meter
Thus, the height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.
Learn more about trigonometry here:
brainly.com/question/26719838
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