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olga55 [171]
3 years ago
7

Question 1 of 10

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

<h3>22 ÷ 0 = 0 </h3>

<h3>So ur Answer is 0 .</h3>
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viva [34]

Step-by-step explanation:

Given g'(x) = g^{-2}, x> 0\ g(1) = 0 \ and \ g(2) = 0

To get g(x), we will have to integrate g'(x)

g(x)  = \int\limits {x^{-2}} \, dx\\ g(x)  = \frac{x^{-2+1}}{-2+1} + C\\ g(x) = -x^{-1} + C\\g(x) = -x^{-1} + C\\

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0 = -1⁻¹ + C

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Substitute C = 1 into the function

g(x) = -x⁻¹ + 1

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3 0
3 years ago
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