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Finger [1]
3 years ago
13

What is the sum of the first 19 terms in the arithmetic sequence 3+7+11+...

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0
3,7,11,15,19,23,27,31,35,39,43,47,51,55,59,63,67,71,75 

You plus 4 every time.
Hope this helped :)
kupik [55]3 years ago
4 0
The sum of the first 19 terms is 3+7+11+15+19+23+27+31+35+39+43+47+51+55+59+63+67+71+75= 741
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The probability that Paul wins a raffle is given by the expression n/n+6. Write down an expression, in the form of a combined si
Elza [17]

Answer:

P(W') = \frac{6}{n+6}

Step-by-step explanation:

<em>Let P(W) represents the probability that Paul wins</em>

<em>Let P(W') represents the probability that Paul does not win</em>

Given

P(W) = \frac{n}{n+6}

Required

P(W')

In probability, the sum of opposite probability equals 1;

This implies that

P(W) + P(W') = 1

Substitute P(W) = \frac{n}{n+6} in the above equation

P(W) + P(W') = 1 becomes

\frac{n}{n+6}+ P(W') = 1

Subtract \frac{n}{n+6} from both sides

\frac{n}{n+6} - \frac{n}{n+6} + P(W') = 1 - \frac{n}{n+6}

P(W') = 1 - \frac{n}{n+6}

Solve fraction (start by taking the LCM)

P(W') = \frac{n + 6 - n}{n+6}

P(W') = \frac{n - n  + 6}{n+6}

P(W') = \frac{6}{n+6}

Hence, the probability that Paul doesn't win is P(W') = \frac{6}{n+6}

6 0
3 years ago
Help me please with this
Paha777 [63]
11) 2x+6y-3; x=5,y=4
the question is asking to evaluate for y when x=5 and evaluate for x when y=4,

2x+6y-3
2x+6y=3

2(5)+6y=3
10+6y=3
6y=3-10
y=-7/6 when x=5

2x+6(4)=3
2x+24=3
2x=3-24
x=-21/2 when y=4

12)
Input Output
N 4(n+3)
12 4(12+3) = 4(15)=60
14 4(14+3)=4(17)=68
18 4(18+3)=4(21)=84
25 4(25+3)=4(28)=112

13)8x+y-10; x=4, y=50
8x+y=10
8(4)+y=10
32+y=10
y=10-32
y=-22 when x=4

8x+50=10
8x=10-50
8x=-40
x=-40/8
×=-5/1=-5 when y=50

14) b is correct

15)c is correct

16) c is correct

If you need explanations on these questions, message me.
8 0
3 years ago
Roger brought some sponges. The number of packages he bought was 14 less than the number of sponges per package. Roger bought 51
mihalych1998 [28]

Answer:

the number of sponges per package bought be 32.5

Step-by-step explanation:

Let us assume the number of sponges per package be x

So the number of packages he bought be x - 14

And, the overall he bought 51 sponges

So

the number of packages of sponges did roger buy is

x + x - 14 = 51

2x = 51 + 14

2x = 65

x = 32.5

So the number of sponges per package bought be 32.5

8 0
3 years ago
- Find the total tax deductions for each of the following weekly paychecks. weekly pay $198.00 $340.00 $250.00 FICA (7.65%) ​
Reptile [31]

Answer:

Total tax deduction per paycheck:

= Weekly pay * FICA tax rate.

Weekly pay $198.00:

= 198 * 7.65%

= 15.147

= $15.15

Weekly pay $340.00:

= 340 * 7.65%

= $26.01

Weekly pay $250.00:

= 250 * 7.65%

= 19.125

= $19.13

3 0
3 years ago
34 ÷ [(7.2 × 0.8) + 3.24]
STatiana [176]

Answer:

3.7777777777 or you could round it to 3.8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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