Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Answer:
14.6316
Step-by-step explanation:
The place value ten-thousandth falls on number 5. The following number is 7 and because 7 is greater than 5, "5" turns into 6.
Hope it helps!
Answer:
12
Step-by-step explanation:
ez claps pie
Answer:
2x+6
Step-by-step explanation:
you want to get 6 more than twice of a number, in this case, x. Hope this helps!
If they are equal then,
5x-3=2x+25
3x=22
X=7 +1/3=7.(3)
