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Vera_Pavlovna [14]
3 years ago
9

What is the missing x-value if (x,1) is a solution of 2x-y=5?

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0
Equation of 2x-y= 5 where we know the y value from (x,1)

We substitute the y value in the equation to get the x value easily

2x-1= 5
2x = 5 + 1
2x = 6
x = 3 (divide both side by 2)

Answer x = 3 when y = 1
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There are 17 red and blue pens, among which r are red. How many are blue? Denote blue pens as b.
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Answer:B=17-R

Step-by-step explanation:

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2 years ago
B. Mason put sticky notes on some pages of his math book. The page numbers for this sequence 3, 5, 8, 13, 21,34, ... Describe th
katrin [286]

Answer:

The next two terms are 55 and 89

Step-by-step explanation:

This is an example of the Fibonacci Sequence: The sum of the previous two numbers equals the next number.

You can see that :

  • 3 + 5 = 8
  • 5 + 8 = 13
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  • 13 + 21 = 24

Rule: the sum of the previous two numbers, equals the next number.

Solve:

  • 3, 5, 8, 13, 21, 34, (21 + 34), (34 + 21 + 34)
  • 3, 5, 8, 13, 21, 34, 55, 89

The next two terms are 55 and 89

-Chetan K

6 0
2 years ago
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Answer to? -12 > -5n + 1n =
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3 years ago
Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

8 0
3 years ago
Read 2 more answers
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