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Ivan
3 years ago
6

Find that slope of a line that passes through each pair of points

Mathematics
1 answer:
Pie3 years ago
7 0
Given two points on the line known as (x1,y1) and (x2,y2): slope = y2y1 x2x1 Page 2 2 Example 1 Find the slope of the line that passes through (1,2) and (3,4). Use the slope equation: slope = y2y1 x2x1 Page 3 3 Example 2 Find the slope of the line that passes through (1,2) and (4,1). That's the basic formula but need
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Find the x- and y-intercepts of the following equation:<br> 2x+3y=-24
Ilya [14]

Answer:

Algebra 

 Topics 

How do you find the intercepts of x2y−x2+4y=0?

Algebra  Graphs of Linear Equations and Functions  Intercepts by Substitution

2 Answers

Gió

Mar 24, 2015

For the intercepts you set alternately x=0 and y=0 in your function:

and graphically:

Answer link

Alan P.

Mar 24, 2015

On the X-axis y=0

So

x2y−x2+4y=0

becomes

x2(0)−x2+4(0)=0

→−x2=0

→x=0

On the Y-axis x=0

and the original equation

x2y−x2+4y=0

becomes

(0)2y−(0)2+4y=0

→y=0

The only intercept for the given equation occurs at (0,0)

Answer link

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How do you use the x and y intercepts to graph a linear equation?

How do you find the x and y intercept for y=2x+3?

How do you find the x intercept for y=2?

What is the y intercept for the y=2 graph?

What is the y intercept for x=−1?

How do you find the x-intercept of the line 

4 0
2 years ago
There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen. How many atoms are there in 600 grams of oxygen? Write your an
tatiyna

Answer:

<u>2.256 x 10 to the power of 25</u>

Step-by-step explanation:

There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen

So, there are x atoms in 600 grams of oxygen

Using the ratio and proportional

So, the number of atoms = 600 * 3.76 x 10 to the power of 22 =

                                          = 6*10^2 * 3.76 * 10^{22}\\=6*3.76 * 10^2*10^{22}\\=22.56 * 10^{24}\\=2.256 * 10 * 10^{24}\\=2.256 * 10^{25}

So, the answer in scientific notation as A.BCD x 10 to the power of E

Will be <u>2.256 x 10 to the power of 25</u>

3 0
3 years ago
Write the solution in interval notation {x| 3 less than or equal to x}
klemol [59]

Answer:

Set in Interval Notation is:  [ 3, ∞)

Step-by-step explanation:

Here, the given expression is:

R  =  {x| 3 less than or equal to x}

Here, the given set is given in the ROSTER FORM of set.

Now, converting the statement in mathematical form, we get:

R  = { x : 3 ≤ x}

So, here: R is the SET OF AL ELEMENTS SUCH THAT each element is either EQUAL TO 3, or GREATER THAN 3.

Writing the st in SET BUILDER FORM, we get:

R = { 3, 4, 5, 6, ....... }

So, R in Interval Notation is:  [ 3, ∞)

4 0
3 years ago
Read 2 more answers
What is the area of the trapezoid?
IRINA_888 [86]

Answer:

69.75 square inches

Step-by-step explanation:

Add the top and bottom lengths then divide by 2 before multiplying it with the height

1/2x(3+12.5)=7.75

7.75x9=69.75

4 0
2 years ago
Read 2 more answers
A need help Dilations-He Said, She Said (12/10)
Elodia [21]

Answer:

We conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

Step-by-step explanation:

Checking the location of the vertices of the original triangle ΔDEF

  • D(-2, 4)
  • E(2, 4)
  • F(0, 2)

Checking the location of the dilated vertices of the image triangle ΔD'E'F'

  • D'(-5, 10)
  • E'(5, 10)
  • F'(0, 5)

Notice that if we multiply the vertices of the original triangle ΔDEF by 5/2, we get the correct image vertices of image triangleΔD'E'F'

i.e.

D(-2, 4) → D'(5/2 (-2), 5/2 (4))  → D'(-5, 10)

E(2, 4) → E'(5/2 (2), 5/2(4))  → D'(5, 10)

F(0, 2) → E'(5/2 (0), 5/2(2))  → F'(0, 5)

Thus, we conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

6 0
2 years ago
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